feat(problem): 6 - sum square difference

src/bin/6.rs

@@ -0,0 +1,43 @@
+/*
+Problem 6 - Sum square difference
+
+The sum of the squares of the first ten natural numbers is,
+1^2 + 2^2 + ... + 10^2 = 385
+The square of the sum of the first ten natural numbers is,
+(1 + 2 + ... + 10)^2 = 55^2 = 3025
+Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.
+Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
+*/
+
+const LOWER_BOUND: usize = 1;
+const UPPER_BOUND: usize = 100;
+
+fn sum_of_squares(lower_bound: usize, upper_bound: usize) -> usize {
+	if lower_bound > upper_bound {
+		panic!("The lower bound must be less than the upper bound!");
+	}
+
+	let mut squares: Vec<usize> = vec![];
+
+	for i in lower_bound..(upper_bound + 1) {
+		squares.push(i.pow(2));
+	}
+
+	return squares.iter().sum();
+}
+
+fn square_of_sum(lower_bound: usize, upper_bound: usize) -> usize {
+	if lower_bound > upper_bound {
+		panic!("The lower bound must be less than the upper bound!");
+	}
+
+	return ((lower_bound..(upper_bound + 1)).sum::<usize>()).pow(2);
+}
+
+fn main() {
+	let squared_sum = square_of_sum(LOWER_BOUND, UPPER_BOUND);
+	let summed_squares = sum_of_squares(LOWER_BOUND, UPPER_BOUND);
+	let difference = squared_sum - summed_squares;
+
+	println!("For the numbers between {LOWER_BOUND} and {UPPER_BOUND}, the difference between the square of the sum and the sum of the squares is {difference}");
+}